Question 234939
Given {{{1/(1-x)=1+x+x^2+x^3+x^4+"..."}}}

calculate:{{{1/(1-x)^2}}}
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{{{1/(1-x)^2 = 1/(1-2x+x^2)= 1/(1-(2x-x^2))=1/(1-x(2-x))}}}

Replace {{{x}}} by {{{(x(2-x))}}} in

{{{1/(1-x)=1+x+x^2+x^3+x^4+"..."}}}

{{{1/(1-(x(2-x)))=1+(x(2-x))+(x(2-x))^2+(x(2-x))^3+(x(2-x))^4+"..."}}}

{{{1/(1-x)^2=1/(1-(x(2-x)))=1+x(2-x)+x^2(2-x)^2+x^3(2-x)^3+x^4(2-x)^4+"..."}}}

Edwin</pre>