Question 234955
It would be 1 minus the probability that it would be 3.


You have 2 dice.


Total possible number of combinations would be 6*6 = 36


Possible ways you could get a 3 would be:


1 + 2
2 + 1


That's only 2 out of 36.


Possible ways you could not get a 3 would be 34 out of 36.


34 out of 36 is the same as 17 out of 18.


Your answer would be A).