Question 234902
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You either meant:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{5}{x}\ -\ 6\ =\ \frac{5}{x}]


or


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{5}{x\ -\ 6}\ =\ \frac{5}{x}]


Either way, there is no solution.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{5}{x}\ -\ 6\ =\ \frac{5}{x}]


Multiply by *[tex \Large x]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 5\ -\  6x\ =\ 5]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 6x\ =\ 0]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ 0]


But 0 is excluded from the domain of the original function.  Therefore no solution.  Or:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{5}{x\ -\ 6}\ =\ \frac{5}{x}]


Cross-multiply:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 5x\ -\ 30\ =\ 5x]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ -30\ =\ 0]


Absurd.  No solution.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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