<PRE><B>Question 234713</B>
suppose that $9000 is invested at an interest rate of 5.4% per year, compounded continuously What is the doubling time? 
I know that the equation is Pe^rt
18000 = 9000e^(0.054t)
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e^(0.054t) = 2
Take the natural log to get:
0.054t = ln(2)
t = [ln(2)]/0.054
t = 12.836.. years
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Cheers,
Stan H.</PRE>