Question 234326
3v^2 + 4v - 1 = 0
{{{v = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
v=(-4+-sqrt[4^2-4*3*-1])/2*3
v=(-4+-sqrt[16+12)/6
v=(-4+-sqrt28)/6
v=(-4+-5.2915)/6
v=(-4+5.2915)/6
v=1.2915/6
v=.215 ans.
v=(-4-5.2915)/6
v=-9.2915/6
v=-1.549 ans.