Question 234272
This seems easy enough if you follow the given directions!
{{{x^2+12x-64 = 0}}} "Move the constant term (-64) to the right side of the equation."
{{{x^2+12x = 64}}} "Multiply each term of the equation by four times the coefficient ({{{4*1 = 4}}}) of the x-squared term."
{{{4x^2+48x = 256}}} "Square the coefficient of the original x-term ({{{12^2 = 144}}}) and add it to both sides of the equation."
{{{4x^2+48x+144 = 400}}} "Take the square root of both sides of the equation." (Note: You should first factor the left side before taking the square root.)
{{{(2x+12)*(2x+12) = 400}}}
{{{(2x+12)^2 = 400}}} Now take the square root.
{{{2x+12 = 20}}} or {{{2x+12 = -20}}}
{{{2x+12 = 20}}}--->{{{2x = 8}}}--->{{{highlight(x = 4)}}}
{{{2x+12 = -20}}}--->{{{2x = -32}}}--->{{{highlight(x = -16)}}}