Question 234289
Find three consecutive odd integers such that three times the second minus the third is 17 more than the first. 
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1st: 2x-1
2nd: 2x+1
3rd: 2x+3
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Equation:
3(2x+1)-(2x+3) = (2x-1)+17
4x = 2x+16
2x = 16
x = 8
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1st: 2x-1 = 15
2nd: 17
3rd: 19
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Cheers,
Stan H.