Question 30594
8(y+2) =(x+6)^2 your equation
8y + 16 = (x+6)^2 distribute the 8
8y + 16 = (x+6)(x+6)  fill in: (x+6)^2 is the same as (x+6)(x+6)
8y + 16 = x^2 + 12x + 36 FOIL
8y = x^2 + 12x + 20 subtract 16
y = (1/8)x^2 + (3/2)x + 5/2

the formula for vertex is (-b/2a, f(x)) in (ax^2 + bx + c = 0)
(-b/2a)
(-3/2)/(1/4)
(-3/2)(4)
-6

f(x) is the y-value
(1/8)x^2 + (3/2)x + 5/2 plug in the -6
(1/8)(36) + (3/2)(-6) + 5/2
9/2 - 9 + 5/2
9/2 - 18/2 + 5/2
-4/2
-2

the vertex is (-6, -2)

the equation for finding foci and directrix is: p=(1/4a)
p = (1/4a)
p = 1/(1/2)
p = 2
since it is positive, the foci will be 2 units above the vertex
the foci should be at (-6, 0)
the directrix will obviously be below, so you go two units down
a point on the directrix should be at (-6, -4), but the directrix is a line:  y = -4

(A) should be the correct answer