Question 234116
Let x = first number

Let y = second number

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x = 2y + 4

Their difference = 11 can be expressed as x - y = 11

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We have two equations in 2 unknowns.

x = 2y + 4...Equation A
x - y = 11...Equation B

Replace x in Equation B with its value given in Equation A and solve for y.

2y + 4 - y = 11

y + 4 = 11

y = 11 - 4

y = 7....This is one of the numbers.

To find x, we plug y = 7 into either Equation A or B (your choice) and solve for x.

I will use x - y = 11.

Let y = 7

x - 7 = 11

x = 11 + 7

x = 18

The numbers are 7 and 18.

If you think about it, 18 is 4 more than twice 7, right?