Question 233492
how do I solve x to the -3 power in parenthesis and a 2 outside the parenthesis? I know for the negative exponent I make it 1/x to the 3rd but how do I square a fraction?
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(x^-3)^2
(1/x^3)^2
= (1/x^3)*(1/x^3) = 1/x^6
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Cheers,
Stan H.