Question 233380
LET X, X+1 & X+2 BE THE 3 INTEGERS.
X(X+1)-3(X+2)=57
X^2+X-3X-6=57
X^2-2X-6-57=0
X^2-2X-63=0
(X-9)(X+7)=0
X+7=0
X=-7 ANS.
-7+1=-6 ANS.
-7+2=-5 ANS.
PROOF:
-7*-6-3(-5)=57
42+15=57
57=57