Question 233485
Doesn't look right.


Your equation is:


X^5-6x-16x^3/ x^3-4x.


Your denominator is equivalent to x * (x + 2) * (x - 2)


Your numerator requires more work.


x^5 - 16x^3 - 6x = x * (x^4 - 16x^2 - 6)


It doesn't appear it can be factored any more than that.


I get:


(x * (x^4 - 16x^2 - 6)) / x * (x - 2) * (x + 2)


The x cancels out and you are left with:


(x^4 - 16x^2 - 6) / ( (x-2) * (x+2) )


I confirmed by making x = 3 and got the same answer with the original equation and with the simplified equation.


Your answer of:


 x^2(x-8)/x-2...... 


does not confirm with the original equation.


My answer would be:


(x^4 - 16x^2 - 6) / ( (x-2) * (x+2) )


That's as far as I could go with it.


Factoring the numerator would require the use of the quadratic formula which would not be a simplification.