Question 233290
{{{2x^2-6x+4=0}}}
{{{x^2-3x+2=0}}}
(x-2)*(x-3) = 0
x = 2 or x = 3
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3y-12=-4x
y = (12-4x)/3
x = 2, y = 4/3
x = 3, y = 0