Question 233305
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The perimeter of a rectangle is given by:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ P_{rect}\ =\ 2l\ +\ 2w]


where *[tex \Large l] is the length and *[tex \Large w] is the width.  Substitute *[tex \Large x] for *[tex \Large w] and *[tex \Large 6x\ +\ 6] for *[tex \Large P_{rect}], and then solve for *[tex \Large l].


Of course this is only correct if we presume that the unit of measure for the width, which you (or perhaps your textbook or instructor) failed to specify, is yards.  You have to make some presumption about the unit of measure for the width or you cannot solve this problem at all.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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