Question 233295
Factor:
{{{m^3+27}}} This can be written as the sum of two cubes:
{{{(m)^3+(3)^3}}}
The sum of two cubes can be factored thus;
{{{A^3+B^3 = (A+B)(A^2-AB+B^2)}}} so...
{{{m^3+27 = highlight((m+3)(m^2-3m+9))}}}