<PRE><B>Question 233123</B>
A charter company will provide a plane for a fare of $200 each for 80 or fewer passengers. 
For each passenger in excess of 80, the fare is decreased by $2.00 per person for everyone. 
What number of passengers would produce the greatest revenue for the company.
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Equation:
Revenue(x) = (80+x)(200-2x)
R(x) = -2x^2 + 40x + 16000
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Maximum Revenue occurs when x = -b/2a = -40/(-4) = 10
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80+10 = 90 would be the number of passengers needed to maximize Revenue.
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Cheers,
Stan H.</PRE>