<PRE><B>Question 233019</B>
Six numbers are chosen at random from the whole numbers between 1 and 16 inclusive, without replacement.
What is the probability that all the numbers are even?
Successful outcomes: 2,4,6,8,10,12,14,16
P(6 even) = (8C6)/16C6 = 28/8008
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What is the probability that all the numbers are odd?
Successful outcomes: 1,3,5,7,9,11,13,15
P(6 odd) = same answer as above.
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What is the probability that at least one of the numbers is odd?
P(at least one odd) = 1 - P(none is odd) = 1-P(all even) = 1-28/8008
= 7980/8008
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Cheers,
Stan H.
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