Question 233026
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Exactly.  Although I would express the slope as *[tex \Large \frac{5}{2}] rather than the slightly more cumbersome but equally correct *[tex \Large \frac{-5}{-2}]


Note: Your value of -5 for the *[tex \Large y]-intercept is correct.  rfer changed the sign on the constant term but failed to divide it by 2.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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