Question 30476
^3 sqrt x^2-4x+2=^3 sqrt x+2
Probably the question is 
[sqrt (x^2-4x+2)]^3 = [sqrt (x+2)]^3  ----(1)
This implies
(x^2-4x+2) = (x+2)
[how? Please look at the model below] 
x^2-4x-x+2-2 = 0 (grouping like terms)
x^2-5x = 0
x(x-5) = 0
x =0 or  (x-5)=0 which gives x = 5
Answer: x = 0 or x = 5
Which is the choice (a) 0,5


Note: Let us evolve a model out of this
[sqrt(p)]^3 =[sqrt(q)]^3
[(p)^(1/2)]^3= [(q)^(1/2)]^3
[(p)^(3/2)]= [(q)^(3/2)]  (using [(a)^m]^n =[(a)^(mn) ——(*)] )
Now raising both the sides to the power (2/3)
[(p)^(3/2)]^(2/3)= [(q)^(3/2)]^(2/3)
{(p)^[(3/2)X(3/2)]}= {(q)^[(3/2)X(3/2)]}
[(p)^1]= [(q)^1] ((using (*) )
That is   p = q
Note: The above steps if we go through repeatedly then 
we will be in a position to just observe and conclude