Question 232816
let the 1st integer be x.

since they have to be consecutive, the 2nd will be x+2, the 3rd x+4 and the 4th x+6.

so,

x+x+2+x+4 = 2(x+6)+2, now solve for x

3x+6 = 2x+12+2
x=8

so substituting 8 for x. the integers are:

8, 10, 12, 14