Question 30531
Let x represent the amount invested in the 10%. Then (x+100) would be the amount invested at 9%. 

Set up the equation: .1x + .09(x+1000)= 150

                      .1x + .09x + 100 = 150
                            .19x + 100 = 150      (subtract 100 from both sides)
                                  .19x =  50      (divide by .19)
                                     x = 263.16

Therefore, the amount invested at 10% was $263.16 and the amount invested in 9% was $1263.16.