Question 232760
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Let *[tex \Large x] represent the measure of side B.  Then the measure of side A is *[tex \Large 2x\ -\ 3], and the measure of side C is *[tex \Large 2(2x\ -\ 3)].


The perimeter is the sum of the measures of the sides:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (2x-3)\ +\ x\ +\ 2(2x\ -\ 3)\ =\ 47]


Solve for *[tex \Large x] to get side B and then calculate the other two sides from that.



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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