Question 232666
Find two consecutive odd integers such that three times the first minus the second equals 24
.
Let x = first of two consecutive odd integers
then
x+2 = second of two consecutive odd integers
.
3x - (x+2) = 24
3x - x-2 = 24
3x - x = 26
2x = 26
x = 13
.
Therefore the two integers are 13 and 15