Question 232614
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x = \frac{-b \pm sqrt{b^2 - 4ac}}{2a} ]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x = \frac{-\left(-\frac{3}{4}\right) \pm sqrt{\left(-\frac{3}{4}\right)^2 - 4\left(\frac{7}{8}\right)\left(\frac{5}{16}\right)}}{2\left(\frac{3}{4}\right)} ]


You can do your own arithmetic on this Halloween horror.  I take it your instructor doesn't like you very much.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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