Question 30502
{{{y=2+3(x+1)^2}}}


Starting with {{{y=x^2}}}, first we move the curve by 1 unit to the left to give {{{y=(x+1)^2}}}, as seen by {{{ graph(300,300,-4,3,-4,10,(x+1)^2) }}}


Next, we stretch it by a factor of 3, anchored still on the x-axis at (-1,0). Look at the graph here and note the y-intercept is now at y=3, instead of y=1: {{{ graph(300,300,-4,3,-4,10,3(x+1)^2) }}}


Finally, we will move the whole curve up by 2 units, so that the vertex is now at (-1,2) and the y-intercept is at y=5: {{{ graph(300,300,-4,3,-4,10,2+3(x+1)^2) }}}


jon.