<PRE><B>Question 232339</B>
let x equal the speed of the slower car in mph.  This means the speed of the faster car is x +30.

If both cars cars are moving towards each other we can add the two speeds together and treat the problem as one moving car.

x +x +30 = 2x +30

distance = (speed)(time)

900 = (2x +30)(8)

900 = 16x +240

16x = 660

x = 41.25mph

add 30 to find the speed of the faster car which is 71.25mph</PRE>