Question 231778
divide:
x^2-9/4 /x^2-6x+9/x^-x-6 
:
Assuming the problem is
{{{(x^2-9)/4}}}
----------
{{{(x^2-6x+9)/(x^2-x-6)}}}
:
Invert the dividing fraction and multiply
{{{(x^2-9)/4}}} * {{{(x^2-x-6)/(x^2-6x+9)}}}
Factor
{{{((x-3)(x+3))/4}}} * {{{((x-3)(x+2))/((x-3)(x-3))}}}
Cancel (x-3) twice; leaving
{{{(x+3)/4}}} * (x+2) = {{{((x+3)(x+2))/4}}}