Question 232133
Let x = the amount invested at 12% per annum, then ($7500-x) would be the amount invested at 10% per annum.
The interest, whose sum is $890, earned on these two amounts can be expressed algebraically as:
{{{x(0.12)+ (7500-x)(0.1) = 890}}} Simplify and solve for x.
{{{0.12x+750-0.1x = 890}}} Combine like-terms on the left.
{{{0.02x+750 = 890}}} Subtracr 750 from both sides.
{{{0.02x = 140}}} Divide both sides by 0.02
{{{x = 7000}}}
The amount invested at 12% is $7,000.00