Question 231934
The equation described would be of the form:
{{{ax^4 + cx^2 = 0}}}
From this equation we can factor out x^2:
{{{x^2(ax^2 + c) = 0}}}
From this we can see that x=0 is a double root (aka root of multiplicity 2). And if {{{3-i*sqrt(7)}}} is a root, then its conjugate. {{{3+i*sqrt(7)}}}, will also be a root.<br>
So the 4 roots are: 0 (twice), {{{3+i*sqrt(7)}}} and {{{3-i*sqrt(7)}}}