Question 231990
A car and a truck leave the same place at the same time. The car is traveling twice as fast as the truck. In three hours time, the car is ahead of the truck by 72 miles. at what rate of speed is each vehicle driving?


Step 1.  Let x be the speed of the truck.


Step 2.  Let 2x be the speed of the car since it is traveling twice as fast as the truck.


Step 3.  Distance= speed * time.


Step 4.  Let 3x be the distance traveled by the truck after 3 hours


Step 5.  Let 3*2x=6x be the distance traveled by the car after 3 hours.


Step 6.  Using Steps 4 and 5, then, 6x-3x=72 since they are 72 miles apart after 3 hours.


Step 7.  Solving leads to {{{3x=72}}} or {{{3x/3=72/3=24}}} or {{{x=24}}} miles per hour.  Then {{{2x=48}}} miles per hour.


Step 8.  ANSWER.  The truck is 24 miles per hour and the car is 48 miles per hour.


I hope the above steps were helpful. 


For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.


And good luck in your studies!


Respectfully,
Dr J