<PRE><B>Question 231893</B>
FIND THE WIDTH OF THE FIELD (X), THE LENGTH OF THE STRAIGHTAWAY (2X) ANS THE 
CIRCUMFERANCE OF THE SEMICIRCLES (2PIR) AND THE AREA OF THE CIRCLE (PIR^2).
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STRAIGHT AWAY=2*2X=4X
END SEMICIRCLES=2PIX=2*3.14X=6.28X
4X+6.28X=5,280
10.28X=5,280
X=5,280/10.28
X=513.62 IS THE WIDTH OF THE FIELD.
2*513.62=1,027.24 LENGTH OF THE STRAIGHTAWAY.
2*3.14*513.62=6.28*513.62=3,225.53 DISTANCE AROUND THE 2 SEMI CIRCLES.
PROOF:
2*1,027.24+3,225.53=2054.48+3,225.53=5,280 DISTANCE OF THE TRACK.
3.14*513.62^2=3.14*263,805.5 AREA OF THE END SEMI CIRCLES.
496.8*939.6=466,793.28 AREA OF THE RECTANGLE. 
466,793.28+233,396.64=700,189.92 FT^2 ANS. FOR THE AREA OF THE FIELD. </PRE>