Question 231960
Hello could you show me how to solve this problem and explain to me how you solved. I am trying to get a better understanding of solving these problems. 
f(x)=2x²-3x
--------------
To solve for x, you find the values of x which make the function = 0
{{{2x^2 - 3x = 0}}}
This one can be factored.
x*(2x-3) = 0
For the product to be 0, one of the factors must be zero.
So either x = 0 or (2x-3) = 0
x = 0 is one solution.
------------
2x-3 = 0
x = 3/2 is the other.