Question 231946
Find two consecutive integers, such that the sum of their squares is 321
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x^2 + (x+1)^2 = 321
2x^2 + 2x + 1 = 321
2x^2 + 2x - 320 = 0
x^2 + x - 160 = 0
*[invoke solve_quadratic_equation 1,1,-160]
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No integer solution.