Question 231862
{{{f(x)=15/(x^2-1)}}}
{{{f(2)=15/((2)^2-1) = 15/(4-1) = 15/3 = 5}}}<br>
{{{g(x) = sqrt(x+4)}}}
The g function, according to the rule above, will take its input, add four and then find the square root. It will do this to <i>any</i> input it is given. So if g is given f(2) as input, g will add four and find the square root:
{{{g(f(2)) = g(5) = sqrt((5) + 4) = sqrt(9) = 3}}}
So the answer is D.