Question 231754
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Sorry.  Not even close.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{9\ -\ x}{5x\ -\ 45}\ =\ \frac{9\ -\ x}{5(x\ -\ 9)}]


But *[tex \LARGE \forall\ a,\,b\ \in\ \R,\ a\ -\ b\ =\ -(b\ -\ a)], so


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{9\ -\ x}{5(x\ -\ 9)}\ =\ \frac{-(x\ -\ 9)}{5(x\ -\ 9)}\ =\ -\frac{1}{5}]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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