Question 231711
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Let *[tex \Large x] represent the smaller number.  Let *[tex \Large y] represent the larger number.  Then:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ +\ y\ =\ 54]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ x\ =\ x\ +\ 9\ \Rightarrow\ y\ =\ 2x\ +\ 9]


Substitute:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ +\ (2x\ +\ 9)\ =\ 54]


Now just solve for *[tex \Large x]. Then subtract from 54 to get *[tex \Large y].



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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