Question 231672
how do you go about solving 
log(x-5)+log(x-2)=1
log[(x-5)(x-2)] = 1
(x-5)(x-2) = 10
x^2-7x+10 = 10
x^2-7x = 0
x(x-7) = 0
Positive solution:
x = 7
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Cheers,
Stan H.