<PRE><B>Question 231630</B>
Three married couples arrange themselves randomly in six consecutive seats in a row. Find the probability of the event of the women being in three adjacent seats, as well as the men. Hint: In this case the denominator of the probability fraction will be 6!=720
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# of ways to succeed
Note: there are 2 sets of 3 consecutive seats in a row of 6 seats
The women can be arranged in 3! ways in their three seats
The men can be arranged in 3! ways in their three seats.
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# of ways to succeed = 2*3!*3! = 2*6*6 = 72
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Probability = 72/6! = 72/720
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Cheers,
Stan H.</PRE>