Question 231590
The digits 1, 2, 3, 4, and 5 are randomly arranged to form a five-digit number. Find the probability of each of the following events.
(a) the number is even.
It will be even if the last digit is even.
# of ways to pick the last digit: 2
# of ways to arrange the remaining 4 digits: 4!
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Total # of 5-digit numbers with the restriction: 2*4! = 2*48
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(b) the first and last digits of the number both are even
# of ways to pick the 1st digit: 2
# of ways to pick the last digit: 1
# of ways to arrange the remaining 3 digits: 3! = 6
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Total # of 4-digit numbers with the restriction: 2*1*6 = 12
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Cheers,
Stan H.