Question 231541
Let 10x + y = the two digit number
:
"has a ten's digit that is two less the unit's digit."
x = y - 2
:
"The number formed by reversing the digits exceeds the original number by three times the unit's digit."
10y + x = (10x + y) + 3y
10y + x = 10x = 4y
10y - 4y = 10x - x
6y = 9x
:
 What is the number.
Replace x with (y-2) in the above equation
6y = 9(y-2)
6y = 9y - 18
+18 = 9y - 6y
18 = 3y
y = {{{18/3}}}
y = 6
then
x = 6 - 2
x = 4
:
46 = the two digit number
:
:
Check solution in the statement:a two-dig
" number formed by reversing the digits exceeds the original number by three times the unit's digit."
64 = 46 + 3(6)
64 = 46 + 18