Question 231530
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Let *[tex \Large x] represent the amount of water in gallons you want to add.  If 5% of the gallon is active ingredient, then 95% is inactive.  Also, you want to end up with 0.75 solution, so 99.25% is inactive.  Note that the total amount of solution in the end will be *[tex \Large x], the amount of water added, plus 1 gallon, the original amount of 5% solution.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 0.95(1)\ +\ x\ =\ .9925(x\ +\ 1)]


Just solve for *[tex \Large x]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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