<PRE><B>Question 231456</B>
Surface area of the original cube is equal to 6 * s^2


If you increase each s by 75%, then each s becomes 1.75 * s.


The surface area then becomes 6 * (1.75 * s)^2


This is equivalent to 6 * 1.75^2 * s^2.


This equals to 18.375 * s^2


Since the original surface area equals 6 * s^2, and the new surface area = 18.375 * s^2, then the new surface area is equal to 3.0625 times the original surface area.


This would be 306.25% of the original surface area which would be an increase of 206.5% of the original surface area.


To see if this is accurate, use some numbers and see if the percentages work out.


Let s = 15


6 * 15^2 = a surface area of 1350.


Increase s by 75%.


s goes from 15 to 15 + .75 * 15 = 26.25


New Surface area is 26.25^2 * 6 = 4134.375


Divide 4134.375 by 1350 to get 3.0625


4134.375 is equal to 3.0625 times 1350 which is an increase of 206.25%


Take 206.25% of 1350 and add it to 1350 to get 4134.375.


It all checks out.


Your answer is that the surface area of the original cube is increased by 206.25%


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