Question 231276
Are these 3 separate problems? If so,
{{{sqrt(3y^2) = sqrt(3)*y}}}
and
{{{sqrt(15y^3z^2) = yz*sqrt(15y)}}}
and
{{{sqrt(24x^8) = 2x^4*sqrt(6)}}}
Note the general rule that
{{{sqrt(a^2) = a}}}
and also,
{{{(sqrt(a))^2 = a}}}
also, I don't know if the signs have been covered
If so,
{{{sqrt(a^2) = a}}}
{{{sqrt(a^2) = -a}}}
since
{{{a*a = a^2}}} and
{{{(-a)*(-a) = a^2}}}