Question 231261
2(x-14)+3x-4x(x-9)=10x+8

You first need to get rid of the brackets by using distribution:

2x-28+3x-4x^2+36x=10x+8

Then set the right-hand side to zero:

2x-28+3x-4x^2+36x=10x+8-10x-8
2x-28+3x-4x^2+36x-10x-8=0

Now collect like terms:

-4x^2+31x-36=0

Now divide everything by -1:

4x^2-31x+36=0

Use the quadratic formula to find:

x=6.33 or x=1.42