Question 231249
We need to come up with the equation of the parabola.

The general equation is:

{{{y=a(x-p)^2+q}}}

The vertex is (p,q). So in our case, p=-1 and q=2.

The amplitude is a. In our case, it is turned downward, which makes it negative. It has the same width was y=2x^2, so our amplitude is a=-2.

Putting it all together:

{{{y=-2(x+1)^2+2}}}

To find the y-intercept, substitute x=0 and solve for y:

{{{y=-2(0+1)^2+2}}}
{{{y=-2(1)^2+2}}}
{{{y=-2+2}}}
{{{y=0}}}

The y-intercept is 0.