Question 231251
We need to have two equations, and two variables.

Let p=number of pennies.
Let n=number of nickels

Eqn 1: p+n=182
Eqn 2: 0.01*p+0.05*n=3.90

Isolate Eqn 1 for n:

n=182-p

Substitute this into Eqn 2:

0.01*p +0.05(182-p)=3.90
0.01*p +9.1-0.05p=3.90

Combine like terms and rearrange to get:

9.1-3.90=0.05p-0.01p
5.2=0.04p

Divide both sides by 0.04:

p=130

You can then find the number of nickels from Eqn 1:

182-130=n
n=52

There are 130 pennies and 52 nickels.