Question 231228
 find the vertex, the line of symmetry, and the maximum value of f(x) graph. 
f(x)=(1/3)(x+1)^2+9
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Vertex: (-1,9)
Max: No max as the parabola opens up
Axis of symmetry: x = -1
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{{{graph(400,300,-10,10,-10,20,(1/3)(x+1)^2+9)}}}
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Cheers,
Stan H.