<PRE><B>Question 231186</B>
Find 3 consecutive odd integers such that twice the 2nd decreased by the 3rd is 3 less than twice the 1st
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1st: 2x-1
2nd: 2x+1
3rd: 2x+3
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Equation 2(2x+1) - (2x+3) = 2(2x-1)-3
4x+2-2x-3 = 4x-2-3
2x-1 = 4x-5
2x=4
x = 2
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1st: 2x-1 = 3
2nd: 5
3rd: 7
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Cheers,
Stan H.</PRE>