Question 30467
this is a very simple question really, just hidden in a lot of jargon.


Imagine the vertical line at x=2.
Imagine the point (-4,1)


Sketch a little hand-drawn graph of these.


Now, for the line x=2 to be perpendicular (ie at right angles) to the line AB, AB must be horizontal...since x=2 is vertical.


As this horizontal line passes through (-4,1), the equation of the line AB is y=1. However, the question doesn't ask for that. It asks for the point on the line AB (equation y=1) so that x=2 is a bisector.


Bisector means it cuts the line AB into 2 equal parts.


So, point (-4,1) is how far from x=2?... x=-4 and x=2? the seperation is 6.


So, the point B, on the other side must also be a distance of 6 away from the x=2 line. This means it mus be ay x=8. So the point is (8,1)


jon.









jon.