Question 231036
1) 6x + 3y = 15
2) kx + y  =  5
.
2) y=5-kx
1)
6x+3(5-kx)=5
6x+15-3kx=5
-3kx=-6x-10
3kx=6x+10
{{{k=(6x+10)/(3x)}}}